(x^2+7x+12)/(x+6)=0

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Solution for (x^2+7x+12)/(x+6)=0 equation:



(x^2+7x+12)/(x+6)=0
Domain of the equation: (x+6)!=0
We move all terms containing x to the left, all other terms to the right
x!=-6
x∈R
We multiply all the terms by the denominator
(x^2+7x+12)=0
We get rid of parentheses
x^2+7x+12=0
a = 1; b = 7; c = +12;
Δ = b2-4ac
Δ = 72-4·1·12
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-1}{2*1}=\frac{-8}{2} =-4 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+1}{2*1}=\frac{-6}{2} =-3 $

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